(2x^2-5x-3)/(x-3)=2x+1

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Solution for (2x^2-5x-3)/(x-3)=2x+1 equation: 



(2x^2-5x-3)/(x-3)=2x+1

We move all terms to the left:

(2x^2-5x-3)/(x-3)-(2x+1)=0



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



We get rid of parentheses

(2x^2-5x-3)/(x-3)-2x-1=0

We multiply all the terms by the denominator


(2x^2-5x-3)-2x*(x-3)-1*(x-3)=0

We multiply parentheses

-2x^2+(2x^2-5x-3)+6x-1*(x-3)=0

We get rid of parentheses

-2x^2+2x^2-5x+6x-1*(x-3)-3=0

We add all the numbers together, and all the variables

x-1*(x-3)-3=0

We move all terms containing x to the left, all other terms to the right

x-1*(x-3)=3

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